Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $3x^{2} + x - 2 = 0$.

(D) Comparing the given equation $3x^{2} + x - 2 = 0$ with the standard form $ax^{2} + bx + c = 0$,we get:
$a = 3, b = 1, c = -2$.
The discriminant $D$ is given by the formula $D = b^{2} - 4ac$.
Substituting the values:
$D = (1)^{2} - 4(3)(-2)$
$D = 1 + 24 = 25$.
Since $D = 25 > 0$,the discriminant is positive and a perfect square.
Therefore,the quadratic equation has two distinct real and rational roots.